To compare cards without the consideration of the suit

Question

I've created this deck and the game is able to get a card for the computer and another one for the player, but when I want to compare the values, the program considers that the suits are in order too.
So, my question is How I manage to put an order to only consider the number and not the suit?

import random

numbers=[2,3,4,5,6,7,"Jack","Queen","King","Ace"]
suits=["Hearts","Diamonds","Clubs","Spades"]
deck=[]
for i in suits:
for j in numbers:
card="{} of {}".format(j,i)
deck.append(card)

random.shuffle(deck)

points_machine=0
points_human=0

card_machine=deck.pop()
print ("The machine has", card_machine)

card_human=deck.pop()
print ("The player has", card_human)

if card_machine>card_human:
print ("The computer wins")
points_machine=points_machine+1
print ("The computer has this punctuation:",points_machine)

Answer 1

I haven't tested it fully (it's getting late now)...copy and paste it to playground or an IDE...

import random

numbers = dict(zip([x for x in range(2, 15)], [2, 3, 4, 5, 6, 7, 8, 9, 10, "Jack", "Queen", "King", "Ace"]))
suits = ["Hearts", "Diamonds", "Clubs", "Spades"]
deck = []
for i in suits:
for j in numbers.keys():
card = (j, i)
deck.append(card)

random.shuffle(deck)

points_machine = 0
points_human = 0

card_machine = deck.pop()
print("The machine has", numbers[card_machine[0]], card_machine[1])
card_human = deck.pop()
print("The player has", numbers[card_human[0]], card_human[1])
if card_machine[0] > card_human[0]:
print("The computer wins")
points_machine=points_machine+1
print("The computer has this punctuation:", points_machine)