What's wrong with this code?

Question

#include <stdio.h>

int main() {
int a=5;
int b=1,c;
printf("Enter no:\n");
scanf("%d",&a);
for(c=a;a>=1:a--)
{
b=b*a;

}

printf("Factorial of given no %d is %d\n",c,b);
return 0;
}

Answer 1

There is an error in syntaxe of for
Change : to ; befor a-- in for loop

Answer 2

Wrong syntax of *for* loop(as mentioned by Youssef Radid )

Here is the fix👇
https://code.sololearn.com/cxsKFs6JZzqj/?ref=app

Answer 3

Hey there, you just did not put semi-colon after a>=1 this.

Your Code After All Error Fixing: -
#include <stdio.h>

int main() {
int a=5;
int b=1,c;
printf("Enter no:\n");
scanf("%d",&a);
for(c=a;a>=1;a--)
{
b=b*a;
}
printf("Factorial of given no %d is %d\n",c,b);
return 0;
}