Homework Python

Question

Hi, I have to write a function which takes list of numbers >=0 and gives me back the second max number in the list.
I cannot sort, change the list or import methods. If the list contains <2 elements it should give me 0
I have to iterate every element only once.

Example:
secondmax([2, 5, 1, 6, 3]) -> 5
secondmax([2]) -> 0
secondmax([]) -> 0

My Attempt: I tried to do smth but it is not much, thanks

Def secondmax(*args):
If type(args) is list:
For x in args:

Answer 1

I think you should try with finding the max() first. Then, find a min() and assign it to a variable. Then iterate through the list and keep re-assigning the value if it is greater than the last one, but still lower than the max.
After the iteration is done, you will get the second max :)

Answer 2

1. Find the max number of the list
2. Iterate through the list returning numbers smaller than the max number
3. Print the new max number

Answer 3

O(n) without any built-in features:
https://code.sololearn.com/czalRkLqGa3W/?ref=app

Answer 4

The function max iterates too.
Is it allowed to use it?

Answer 5

Thank you!

Answer 6

check this one. https://code.sololearn.com/ceNo2rC4GYwe/?ref=app

Answer 7

I think this is still a bit underspecified. What is the expected result when the list contains 2 or more elements that are all equal?

Answer 8

Mostapha Amenchar your code is good but does not seem to solve the above problem. Thanks.

Answer 9

Tibor Santa thats it

Answer 10

Thank you for your comment Marcel. Would you explain to me why? maybe i can improve the code.

Answer 11

Sorry, I forgot to tell that I should iterate through every element only once

Answer 12

https://code.sololearn.com/cEjckip9RO7C/?ref=app