'break' outside loop (SyntaxError) on my first calculator code

Question

https://code.sololearn.com/c8oTUYdJYibM/#py

I don't what i do wrong with the 7th line. I just press 'enter' to go to the next line and type break and when i execute the code, it failed. But if i changed it to for example print('NO'), it's working!
Please enlighten me THX

Answer 1

It's because there is no loop to be broken there. Use exit() instead :)

Answer 2

M.O.HONOR
break - keyword works only for breaking out of the loops like for and while .
To quit of if block use exit() function which terminates program execution

Answer 3

Thx a lot both of u :)