why this code is not working

Question

import re

q=input("")

pattern=r"[a-z][A-Z]+"

match = re.search(pattern,q)

if match==match:
print('Deja Vu')
else:
print("Unique")

Answer 1

I don't know where you copied this code from or why did you thought it would work,i have no idea about regular expression but what is really "match== match"?lol!

also I tried printing match after entering some string ,value of match is None

Basically you are comparing None=None

Answer 2

you can sort that regular xpresion like this [a-zA-Z]+

Answer 3

I agree whit Abhay you must validate if match equals true
Something like this
if match:
# your code

Answer 4

To add to the other issues pointed out already, your regex searches for a lower-case letter, followed by 1 or more upper-case letters. This is not what the task is asking for.

Answer 5

Abhay I copied my code from code coach

Answer 6

The issue with your regex now is that it will match any string of letters, upper or lower-case, and there is no requirement for those letters to be the same.

If you are not fairly fluent in regex, then this is a tricky one to do. You need a capture group to capture a letter, then you need to use back-reference to try to match the same letter as you had in the capture group later on. It is hard to describe without just showing you the answer, and I always recommend learning things by yourself.

If you do want to learn regex more deeply, I would recommend Automate The Boring Stuff as it has a great tutorial on regex. https://automatetheboringstuff.com/2e/chapter7/

Answer 7

https://code.sololearn.com/cSBPTG9PnsuI/?ref=app
use that

Answer 8

Russ ,Emanuel Maliaño,Abhay
import re

q=input("")

pattern=r"[a-zA-Z]+"

match = re.search(pattern,q)

if match==True:
print('Deja Vu')
else:
print("Unique")

still this code is not working