Explain this code??

Question

def fun(a, p=0):
if(p==len(a)):
return 0
z=1 if not a[p] else 0
return z + fun(a, p+1)
a = [1,0,1,1,0,1,0]
Print (fun(a))

#output
3

Answer 1

Emon Your function calculates and print the number of times zero appears in your list a.

Try to put more zeros by adding elements with value zero like this:
a[1,0,0,4,2,0,0,0,0,0,5,3,6,9]
And run it.
Surprisingly it counts zeros and returns the number of times they are there

Except when it is a number with zero like 10,450,30 etc