For loop in a for loop

Question

The output is 7 (and not 8) for

int x;
for(x=0; x<4; ++x) {
for(int y=0; y<4; ++y) {
x=x+y;
}
}
cout<<x;

What is the logic for this?

Answer 1

The output is 7
Because
1st run x=0
2nd run x=1
3rd run x=3
4th run x=6
And it comes out from the for(y)
After Increment in for(x) x=7, checks the condition and comes out.☺️

Answer 2

Did question changed or I read it wrong ?

I calculated for this
int main() {

int x;
for(x=0; x<4; ++x) {
for(int y=0; y<4; ++y) {
x=x+y;
}
cout<<x;
}

return 0;
}

Answer 3

Abhay as Krishna vamsi explained, when the 'y' loop is over, x is 6.
However, it doesn't quit directly the 'x' loop, since à for loop is structured like this :

- condition
- block
- increment

So it increments 'x', checks if 'x < 4' and exits the loop.

Answer 4

Well the output is 6 ,I had to even run it in playground to make sure as I calculated it was 6 by writing but cudn't figure out how it is 7 or 8🤔

Answer 5

Abhay Yes, he changed question. Previous he forgets one }

Answer 6

I don't think it's a good idea to alter loop counter value except for incrementing/decrementing it per loop cycle.

Just saying ...