Can anyone explain this ?

Question

#define square (x)(x*x)
int main() {
x = square (y+1);
printf("%d\n",x);
return 0 ;
}

Answer 1

It will be calculate like this if y =1;
x=square (1+1)
square (x) x*x which means 1+1*1+1 so answer will be 3
If it will be x=square (2+4)
Then it will be
2+4*2+3 hope u understood

Answer 2

Yes the value of y is 1

Answer 3

Thank you . I got it .

Answer 4

The answer is 3 but how ?

Answer 5

square(y+1) is replaced at compile time by :
(y+1*y+1)

I think y is 1 in your code (you didn't show it here, so I don't know the value of y). So :
1 + 1*1 + 1 = 3