FUNCTION OVERLOADING

Question

#include <iostream>
using namespace std;

void printNumber(int x) {
cout << "Prints an integer: " << x << endl;
}
void printNumber(float x) {
cout << "Prints a float: " << x << endl;
}

int main() {
int a;
cin >> a;
float b;
cin >> b;
printNumber(a);
printNumber(b);
}

I tried working a little bit with the code and I discovered that once one inputs a floating point number where there is supposed to be an int, it rounds off the number to its correct syntax i.e
int a;
cin >> 4.32;
//cout is 4

float b;
cin >> 4;
// cout is 0.4

Anyone who knows why it doesn't give an error but rather just returns the correct value?

Answer 1

Thanks codemonkey for the answer

Answer 2

Please correct your example to prevent misunderstanding Simangolwa Lifwatila

cin >> 4.32; // should be cin >> a;

cin >> 4; // should be cin >> b;

Answer 3

Ipang I was trying to illustrate the question in a way that will be understood thats why my syntax was like that. But thanks for that.