Why is it giving me o/p str when i give input as integer value btw 1 to 1000

Question

s=input()
l1=[i for i in range(0,1000)]
if s in l1 :
print("int")
else:
print("str")

Note1:even if it is float(eg:2.0) its ok to call it as "str"
Note2: input 43a must give str

Answer 1

Hi remember that python input is by default a string result, so if you want to achieve what you want you have to cast your input into a integer, like this
s=int(input())

Answer 2

Im sorry but the question has a string input - you have been using ast.literal.eval() to take input in a suitable format . Have you thought of how does it distinguish btw different types of data structures? You will be given a string as input . U have to determine int or str ?
This is also encountered in data science. Upon taking a lot of data , sometimes integer values are treated as string, eg : 43a is str 12.4 is str

Answer 3

input() function in python can only access data in the form of strings data type only...
To convert that to required suitable type, we have type casting methods..
So ex : 1 is different from "1"...