Question about dictionaries

Question

pairs = {1: "apple",
"orange": [2, 3, 4],
True: False,
None: "True",
}
print(pairs)
I'm a beginner. Could somebody explain to me why does this code print 1: False instead of 1: "apple"
and doesn't print True: False.

Answer 1

Sava
True is the same as 1 and 0 is the same as False.
Now, since you can't have keys of the same variable name (or value in this case) in a dictionary, the first key is chosen.

Hope this helps 😃😃

Answer 2

Myself and Jan Markus already explained this.
The most recent 1 will be outputted
Eg. Let's add another True

pairs = {1: "apple",
"orange": [2, 3, 4],
True: False,
None: "True",
True: 'programmer'
}
print(pairs)

Output: 1: programmer,...

Answer 3

Thank you
But I still don't understand why does the algorithm then print 1:false before orange

Answer 4

Thank you

Answer 5

I'm going to complicate things for you... my Python knowledge is a little out of date and I've just read that since 3.7, dictionary ordering can be guaranteed on insertion order. That means one of 2 things, either:

1) You are using an older version of Python

Or

2) The behaviour is as such that the first key (1) remains in position 0 as it was inserted first and then the value is over-written when the subsequent pairs are added.

Answer 6

When selecting a value from a dictionary or a list or an array for example, python uses zero-based indexing.this means that it starts counting at zero and not one as you may have expected.so the first value on the dictionary is on index 0

Answer 7

Dictionaries are not ordered so they will not necessarily output in the order they are written.

Answer 8

In order to get the desired result you may use : print(pairs[1])

Answer 9

The latest question was regarding order of output, not key uniqueness.

Answer 10

Yes I understood that but did not get why is it printed first instead of orange:[2,3,4] .