+ 2
Making a login
Would this code work on windows? Is there a way to check of string values? I tried to run it on here and got an error about "Wulfy" not being declared. I dont want answers i want a good explantion please. Thank you guys :) #include <iostream> //#include <Windows.h> #include <string> using namespace std; int main() { string name; string pass; cout << "Login with provided Information\n" << "Username:"; //Sleep(5000) cout << "Password:\n"; if (name == Wulfy && pass == Wulfy) //Login name and Password { cout << "Accepted"; } else { cout << "Denied"; //Sleep(10000); //return 0; // this code above here is for if it was on a windows computer } }
5 Answers
+ 2
Its cin
+ 2
#include <iostream>
//#include <Windows.h>
#include <string>
using namespace std;
int main()
{
string name;
string pass;
string Wulfy = "Wulfy";
cout << "Login with provided Information\n" << "Username: \n";
cin >> name;
//Sleep(5000)
cout << "Password: \n";
cin >> pass;
if (name == Wulfy && pass == Wulfy) //Login name and Password
{
cout << "Accepted";
}
else
{
cout << "Denied";
//Sleep(10000);
//return 0;
// this code above here is for if it was on a windows computer
}
}
0
Thanks man, i fixed up the code a bit