How did this result come out is 8181?

Question

int x=80;
int &y=x;
++x;
cout<<x<<y;

Answer 1

If You Want Explanation Then Here I Am Telling You Step By Step
First You Initialised And Declared An Integer Type Variable With Value 80 Now After That You Initialised A Reference Variable y which is holding address of variable x
and when you performed pre increment on x this will increase the value of x by 1 so when you printed x this gave you 81 and when you printed y who’s pointing to x first go to memory location of x then printed the value of x which is 81 SO ATLAST YOUR OUTPUT WILL BE 8181.
This Is The Easiest Way I Can Explain This To You Vladimir

Answer 2

This post will help u to understood the concepts of reference variable

https://www.geeksforgeeks.org/references-in-c/amp/

Answer 3

Okay You Want Explanation About How This Code Gave You Output 8181 ?

Answer 4

Yes 8181.

Answer 5

Int &y=x means that if you increase x or y second also changed since both variables link the same memory. But if you write int y=x in this case you will create copy of x value. So bot variables in this case link to different memory

Answer 6

Absolutel right!
First go to memory location x and then print the value of x.
x=81 and y=81.

Answer 7

Thanks george I Just Mismatched With Terms

Answer 8

Vladimir budut voprosi po c++ pishite v lichku pomogu chem smogu

Answer 9

Ryan Daniel not pointer but reference! There are a big difference between pointer and reference

Answer 10

Ryan Daniel you are welcome! The great explanation!