How comparing two arrays if are equall

Question

example:
num=[9,4,6] numbers=[6,7,0]
if ( num==numbers){alert ("hi")}

Answer 1

Comparing anything in JS is quite tricky, always be clear about the conditions you consider true. Should it be == or ===?
When comparing arrays two questions pop up:
1. does order matter, i.e. is [1,2] equal to [2,1], then you should sort both first.
2. Do you want shallow or deep compare, I.e. does [{value:1}, 2] equal to [{value:1}, 2].

Just pointing it out. Had a few debugging nightmares due to bad equal conditions. 😁😁😁

Answer 2

I need this for the function win() in my code
OrderTheNumbers.
Thanks guys I'll see if it works....I am a little confused

Answer 3

the program works anyway but the function win ()
looks like a 7year child's code

Answer 4

@Nikolay thanks
nice code. It works.

Answer 5

@STEVEN an example?

Answer 6

function comp(a,b) {
return (a.length != b.length) ? false : a.reduce(
function(r,v,i,a) { return (r) ? (v==b[i]) : false; },
true
);
}

// if a content == b content return true, else false...

Answer 7

@Didi, here is how I would do it. That way you can easily extend to 16, 25, .... numbers :D

function win(){

var numbers = document.getElementsByClassName('numbers');
var win = true;
for (var i in numbers) {
if ( numbers[i].innerHTML != numbers[i].id ) {
if ( numbers[i].id != numbers.length ) {
win = false;
break;
}
}
}
if (win) {
alert(" YOU WIN\n You made "+step+" moves") ;
}

Answer 8

i don't know there is any method or not..but you can use for loop....
for(i=0;i<3;i++)if(num[i]!=numbers)count++;if(count==0)print hi