Why this code is not right?

Question

https://code.sololearn.com/cHlsiwudL6BE/?ref=app

Answer 1

Try in this way:-

#include <iostream>
using namespace std;

int main() {
int N;
int evens=0;
int odds=0;
int zeroes=0;
cin >> N;
for (int num=0; num<=N; num++) {

if (num==0) {
zeroes++;
}
else if (num%2==0) {
evens++;
}
else if (num%2 != 0) {
odds++;
}
}
cout << "The number of zeroes is " << zeroes << endl;
cout << "The number of evens is " << evens << endl;

cout << "The number of odds is " << odds;
return 0;
}

Answer 2

I don't know why were you priting counts of number within loop..
And just check for zero before checking even

https://code.sololearn.com/c7WqlPDuTgtg/?ref=app

Answer 3

Can you give some numbers to check with?

Answer 4

One issue I found is that 0 is counted as evens, not zeroes.

Answer 5

Problem is thar num%2==0 gives true also when num is 0, so you have to reorder your IF's

If (num==0) ...
else if (num%2==0)...
else /* if (num%2!=0) */ ...

Answer 6

if num % 2
print it's odd, increment <odds>
else
if num
print it's even, increment <evens>
else
print it's zero, increment <zeroes>

Answer 7

#include <iostream>
using namespace std;

int main() {
int N;
int evens=0;
int odds=0;
int zeroes=0;
cin >> N;
for (int num=0; num<=N; num++) {

if (num==0) {
zeroes++;
}
else if (num%2==0) {
evens++;
}
else if (num%2 != 0) {
odds++;
}
}
cout << "The number of zeroes is " << zeroes << endl;
cout << "The number of evens is " << evens << endl;

cout << "The number of odds is " << odds;
return 0;
}

Answer 8

There can be at the most 1 zero,. N mod 2 gives whether the number is even or odd and you can take the respective sum 🤔

Answer 9

I did but something is not ok

Answer 10

Tell the input that shows wrong output

Answer 11

boonga important info, khm.

Answer 12

0 is even

Answer 13

OF THE TOPIC

0 and 1 are imagenary
2,4,8,10... are even numbers
3,5,7,9.... are odd numbers

Based on Square Theory.

Does MODULUS is dependent on that theory ?

0 % 1 = 0
1 % 1 = 0
2 % 1 = 0
...

How to transform this equation?

That's why modulus is mapping.

Modules derives that number is odd or even in programming.

Answer 14

OFF THE TOPIC

Higher Mathematics

√(-1) = √(-1)
√(-1)*1 = √(-1)
√(-1)*√(-1)*√(-1) = √(-1)
(-1)*√(-1) = √(-1)
- √(-1) = √(-1)
2*√(-1) = 0

This implies
√(-1) = 0
or
2 = 0 / √(-1) ... (I)

Assume √(-1) = iota

(0 * √-1) / (√-1)*(√-1) = 2
(0 * √-1) / (-1) = 2
(0 * √-1) = -2....(ii)

From equations (i) & (ii)
Division
(0 * √-1) / (0 * √-1) = 2 / -2
1 = -1
2 = 0

This tells that 2 is also imagenary.
iota is vector √-1 called i

x + iy + p + iq = (x + p) + i(y + q)

x + iy + p - iq = (x + p) + i(y - q)

(x + iy)*(p + iq) = (xp - yq) + i(xq + yp)

(x + iy)/(p + iq) = ( (xp - yq) + i(xq + yp) ) / (p*p + q*q)

Examples of complex numbers. Very useful in

image analysis
sound analysis
vector calculation
hyperbolic functions
sine cosine calculation using series

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