Pls what is wrong with this code

Question

For 'That's odd' challenge
a = input().split()
b = ''
for x in a:
if int(x) % 2 == 0:
b += '+' + x
c = eval(b)
print(c)

Answer 1

https://code.sololearn.com/crg4Y16g7zA8/?ref=app

Answer 2

Abdulhameed
Print value of variable <b> before you send it to eval(). Once you do that, you will understand what the problem is👍

Answer 3

Abdulhameed I just fixed: eval, str+int, len(b)==0

Answer 4

It is working on my windows IDE and on sololearn playground

Answer 5

Ipang
Thank you
I understand now👍

Answer 6

M.d Nasif
Your code worked, Thanks
But I don't understand why mine did not work can you explain to me
Maybe I did not get the question correctly

Answer 7

Thanks guys
I was able to solve
But can anyone explain to me why mine did not work

Answer 8

Why people are suggesting alternative solutions lol !
When you input something like
40 40 and even 45 40 , that works fine ,since b isn't empty when evalutes but when input is something like 45 45 then b is just an empty string which isn't a valid python expression and so you get the error ,now you can google more about what python expressions are considered valid by eval function!

Answer 9

The error it is showing is
Line 6
c = eval(b)

Answer 10

here is my solution, hope it will help.

https://code.sololearn.com/czrrnkkXuLY3/?ref=app

Answer 11

Addulhameed

b += '+' + x

char can't be added to char

b is char variable
'+' is char leteral
x is also char variable

not considered as valid operands for + operator.

DHANANJAY PATEL

Answer 12

Here is my solution

n = int(input())
l = [int(input()) for i in range(n)]

print(sum(list(filter(lambda x: x % 2 == 0, l))))