is the class type of Arbitrary Argument, (*args) in python 'list' or 'tuple'?

Question

x, *args= 1,2,3
print(type(args)) # <class 'list''>

def print_type(*args):
print(type(args)) # <class 'tuple'
print_type(1,2,3)

The first print statement outputs 'class list' while the second outputs 'class tuple'. Why is that?

Answer 1

Because *args gives you a tuple. anything in a sequence without explicitly placing parenthesis around them makes it a list rather than tuple.
If you want 1,2,3 as a tuple, check:
type((1,2,3))

Instead of printing the type, try printing them out and see for yourself

Answer 2

Slick tnx a lot.