What is method overloading in java?

Answer 1

say you have a method that does one thing...it takes parameters of the same type and has a return type of the same type.overloading is evident when you take the same method and Change the return type and the data type of the parameters to suit your needs.keeping in mind that the method is the same.

take this as an example:

//original method

public int area(int a,int b){
area = a * b;
return area;
}

//overloaded method

public double area(double a,double b){
area = a * b;
return area;
}

Answer 2

Methods with same name but different parameter lists. Parameter lists may differ in the following ways:

1. data types

int result (int a)
int result (double a)

2. order of data types

int result (int a, double b)
int result (double b, int a)

3. number of parameters

int result (int a)
int result (int a, int b)

Answer 3

thank you Shamima, Mirko, Samuel

Answer 4

thank you Tashi!

Answer 5

Thank you Syeda...super helpful C++ is helpful for Java

Answer 6

I've got a simple example at the playground:
https://code.sololearn.com/cJmmki0zu8Fv/?ref=app
I hope that will help better than a definition ^^ Tell me if you have further questions.

Answer 7

Overloading Operator.....

C++ allows you to specify more than one definition for a function name or an operator in the same scope, which is called function overloading and operator overloading respectively.

An overloaded declaration is a declaration that had been declared with the same name as a previously declared declaration in the same scope, except that both declarations have different arguments and obviously different definition (implementation).

When you call an overloaded function or operator, the compiler determines the most appropriate definition to use by comparing the argument types you used to call the function or operator with the parameter types specified in the definitions. The process of selecting the most appropriate overloaded function or operator is called overload resolution.
***************************************************************************
Function overloading in C++:

You can have multiple definitions for the same function name in the same scope. The definition of the function must differ from each other by the types and/or the number of arguments in the argument list. You can not overload function declarations that differ only by return type.

Following is the example where same function print() is being used to print different data types:

#include <iostream>
using namespace std;

class printData
{
public:
void print(int i)
{
cout << "Printing int: " << i << endl;
}

void print(double f)
{
cout << "Printing float: " << f << endl;
}

void print(char* c)
{
cout << "Printing character: " << c << endl;
}
};

int main(void)
{
printData pd;

// Call print to print integer
pd.print(5);
// Call print to print float
pd.print(500.263);
// Call print to print character
pd.print("Hello C++");

return 0;
}
When the above code is compiled and executed, it produces the following result:

Printing int: 5
Printing float: 500.263
Prin

Answer 8

you can have more than 1 method with the same name but with different parameters, ie:
~public string name(int a){}
~public string name(inta, int b){}