Why Result is 2 not 1 ? a() method already defined in both A&B . How to call the super class method from child class in this par

Question

class A:
def a(self):
print(1)
class B(A):
def a(self):
print(2)
class C(B):
def c(self):
print(3)

c = C()
c.a()

Answer 1

2

Answer 2

pretty clear thanks lord 👌. Result as following:
>>>
1
None # why None ?

def a(self): # what is the need of a() in C
super(B,self).a() # this call a() in A , Why ??
super().a() # but this call a() in B , Why ??

Answer 3

What is the result of this code?
class A:
def a(self):
print(1)
class B(A):
def a(self):
print(2)

class C(B):
def c(self):
print(3)

c = C()
c.a()

output:2

Answer 4

What is the result of this code?
class A:
def a(self):
print(1)
class B(A):
def a(self):
print(2)

class C(B):
def c(self):
print(3)

c = C()
c.a()

Ans: 2

Answer 5

What is the result of this code?
class A:
def method(self):
print(1)

class B(A):
def method(self):
print(2)

B().method()

output:2

Answer 6

Thanks ,Do I really need to define a() method in C to be able to call the super class A. when I tried super(B,self).a() without def a() : in C >>> 2 , still refering to the Base class not the Super.