How to use if and else conditions while dealing list data?

Question

numbers = [13, 5102, 45, 2301.40, 203, 1502, 3]

1. Set the value of the variable numbers_sum to be the sum of all the numbers in the list numbers.

2. By using a built-in function, complete the ifstatement. If our list has at least one member, we want to print the mean; otherwise, we want to print the number 0.

Answer 1

Did it worked??

Answer 2

To check if list numbers has elements, you can also use: if numbers:
Here is the sample:

numbers = [13, 5102, 45, 2301.40, 203, 1502, 3]
if numbers:
print(sum(numbers)/len(numbers))
else:
print("0")

Answer 3

and you can use sum function to find out the sum of numbers in the list

Answer 4

your first if statement shoulf be:

if len(numbers):

# all it wants is for you to check if the list is empty

Answer 5

Abhi

numbers = [13, 5102, 45, 2301.40, 203, 1502, 3]
number_sum=sum(numbers)

#you have to check wether the list is empty or not

if numbers: #as suggested by Lothar

print(number_sum/len(numbers))
else:
print("0")

Answer 6

Try using print(0) instead of print("0")

Answer 7

Hi Akshay,

I tried with that option as well but not passed the test case

1. numbers = [13, 5102, 45, 2301.40, 203, 1502, 3]
2. number_sum=sum(numbers)

if (numbers_sum)>= 1 :

print(numbers_sum/len(numbers))
else:
print("0")

Answer 8

Thanks Akshay,

final code as follows

if len(numbers)>= 1 :

print(numbers_sum/len(numbers))
else:
print(0)

Answer 9

Hi Akshay,

Yes it worked at last.

Answer 10

use a loop to loop through the list.
use if amd elif statements to check things
print out what yod like.

please show an attempt

Answer 11

Hi Lothar, Akshya, Slick,

Thanks for your prompt replies but none of them are fix the issue as I mentioned earlier we need to verify the list total is greater than 1 or not first if yes then only we need to print mean of the listed values else print as "0" so please explain what did I miss in my attempt?

if (numbers_sum)>= 1 :

print(numbers_sum/len(numbers))
else:
print("0")