Python name generation with out repeating

Question

(Long Question) If I am making a game that has tasks for one sometimes two players. How would i randomly generate the second players name without running the risk of repeating the same name?

(Short Question) How do i randomly generate 2 names with out running the risk of repeating?

Answer 1

the principle is rather simple:

- create a list with n names
- select ramdomly the first name
- select randomly the second name and compare it to the first:
- if the second name is identical with the first name, repeat the selection of the second name

Answer 2

Tom Klein , it would be great if you could post us your current try in coding for this task. this makes us able to help you. Thanks!

Answer 3

Tom Klein , see my comments for you in the attached file.
https://code.sololearn.com/c3TFbrFR4lRN/?ref=app

Answer 4

What would the code be to compare? Would it be:

if x == x
run again

?

Answer 5

def select_player():

import random
players= ['Tom', 'Crystal', 'Joe', 'James', 'Morgan']
print (random.choice(players))
#print(value)

print('\n')

select_player()

# E=000-299/a-zz
# M=300-699/aaa-azz
# X=700-999/baa-bzz

def select_card():

rating = input()
if (rating == "e"):
import random
lis = []
lis += list(range(17, 18))
value=(random.choice(lis))
if (rating == "m"):
import random
lis = []
lis += list(range(1, 45))
lis += list(range(300, 331))
value = (random.choice(lis))
#print(value)
if (rating == "x"):
import random
lis = []
lis += list(range(1, 45))
lis += list(range(300, 331))
lis += list(range(700, 731))
value = (random.choice(lis))
print(value)
#print (value)
print ('\n')
def two_player():
cards = (17, 39, 40, 45, 300, 302, 308, 315, 319, 323, 330, 703, 704, 705, 718, 719, 720, 724, 727)
for number in cards:
if number==value:
select_player()
print ('***If the same name gets picked twice***\n***the rest of the group gets to decide***\n ***your parnter***')
print ('\n')

two_player()