Why this code output is 0?can anyone elaborate this

Question

int exp= 1?0:2?3:4;
printf("%d",exp);

Answer 1

What i was thinking is since 0 is answer for 1 value 0?3:4 will be taken..so since 0 is false 4 will be printed thats what i thought off

Answer 2

Thanks mate appreciate for that reason and suggestion

Answer 3

Ternary operator
exp1 ? exp2 : exp3

If exp1 is is nonzero then exp2 is evaluated and it becomes the value of the whole expression otherwise exp3.

1 ? 0 : (2 ? 3 : 4);
1 is nonzero so 0 is the result of the expression.
int exp = 0;

Answer 4

Be careful when nesting ternary operators. Add parenthesis for readability and it also prevents from logic/syntax errors.