[Java] Dividing by zero did not give error

Question

For the following code:

double x=-1.0/0.0;
System.out.println(10.0/x);

The output was -0.0

My questions are 1) Why doesn't the first line itself give any error? and
2) Why is there a negative sign with zero? Is 0.0 different from -0.0??

If this question has been asked before, please provide a link. Thanks in advance!

Answer 1

That's because JVM only throws arithmetic exception when divided by int 0
If you divide by floating-point 0.0 result will be infinity.
Here the sign is "-"
If you try to print x,
System.out.println(x);
You'll see it results in -Infinity

Now when you divide any number by -infinity it'll result in -0.0

https://www.javamadesoeasy.com/2015/12/when-dividing-by-zero-does-not-throw.html?m=1

Answer 2

Basically JVM doesn't throw an exception for float pointing number . It gives output in-form of infinty/-infinty or NaN
Eg:-
Float a = 0.0f
Float b = a
System.out.print(b/a);
//For this code output will be "NaN"

Float a = 1.0f
Float b = 0.0f
System.out.print(a/b);
//For this output will be "infinity"

Float a = -1.0f
Float b = 0.0f
System.out.print(a/b);
//For this output will be "-infinity"

Answer 3

Oh okay!! Thanks!