How does this output comes? In C

Question

Please help me to understand how does this output comes....

And also tell me, how it was working....

Here that code.....

https://code.sololearn.com/cIk4gM5PPF1u/?ref=app
https://code.sololearn.com/cIk4gM5PPF1u/?ref=app

Answer 1

p[2] can be referred to as *(p+2)

Answer 2

You initialised an array and a pointer to store the address of integer variable.

By using * operator we can access the value of a variable through a pointer.

In your printf statement you accessed the value of address 2 of a[p] would give us the value of the variable stored in address 2 subsequently.

Thus the answer comes out as 2.

Answer 3

Interesting! As Arsenic said, it seems that, by ommiting the *, it can reference the entire array instead. It also seems that the arrays a and p are linked, so if you do a[2] = 42 in the line before the printf statement, it will output 42.

Answer 4

Thanks to all....😊🙏

Answer 5

an array name is a pointer itself, it points to the first element address, and to other elements as you increment it.