How can this programme give this output?

Question

#include <stdio.h>

int main() {
int i = 2, j = 3, l ;

l = j / i * i ;

printf( "%d", l) ;
return 0;

Why does this code return l as 2? Like, how could it possibly ?

Answer 1

remember that if you work with integers, you will get integers as a result, the decimals will be ignored. You can also try different results by changing the order of the operation using parentheses, such as: l = j / (i * i);
// Result: 0

Answer 2

3/2 = 1
1*2 = 2

Answer 3

Yeah I get it now, thanks so much

Answer 4

Ohhhh, thanks