Python - Sum of all digits error

Question

Hi guys I'm really need help now
cuz at my code, calculating only functions at under 100.
I really can't find why is this not working over 101
PLz help me

n = int(input())
r = n
length = 0

while n>0:
n //= 10
length += 1

L = int(length) - 1

Z=0
while r != 0:
if not L == 0:
Z += r//(10**L)
r -= (10**L)*Z
L -= 1
elif L == 0:
Z = Z + r
r = 0
break

print(Z)

Answer 1

Change this part:
Z += r//(10**L)
r -= (10**L)*(r//(10**L))

Answer 2

If you are trying to sum the digits in say, 257 which will be 14. You could do it this way.

num = 567
add = 0
for i in str(num):
add += int(i)

print (add) # 18

Check out this code for other ways.

https://code.sololearn.com/cTgx4gYfpto8/?ref=app

Happy Coding 😀

Answer 3

Thank you so much Julia , Tomiwa :)
Yall legend!! really appreciate it