Leap Year

Question

I want to write a C Code where user could give a 4 Digit Year number like :2018 The programm will say if its leap or not leap year. But i want to add another step. Ex: if 2019 is not the leap year the programm shoudl tell me which year is next leap year.

#include <stdio.h>
int main() {
int year;
printf("Enter a year: ");
scanf("%d", &year);
// leap year if perfectly visible by 400
if (year % 400 == 0) {
printf("%d is a leap year.", year);
}
// not a leap year if visible by 100
// but not divisible by 400
else if (year % 100 == 0) {
printf("%d is not a leap year.\n", year);
}
// leap year if not divisible by 100
// but divisible by 4
else if (year % 4 == 0) {
printf("%d is a leap year.\n", year);
}
// all other years are not leap year
else {
printf("%d is not a leap year.\n", year);
}
year+=1;
printf("%d is the next leap year:\n", year);

return 0;
}

Answer 1

You can just check if the year is divisible by 4, this is the only necessary and also sufficient condition to be a leap year.

In case the year is not a leap year you can add to it (4- year%4) and you got the next leap year

edit: oh I apologize for my ignorance, being divisible by 4 is not sufficient.

Answer 2

CarrieForle sorry I didn't know exactly about leap years till minutes ago and I was confused 🤯
Now the code should work right

Answer 3

if (yr % 400 == 0 || (yr % 100 != 0 && yr % 4 == 0)) {
// Leap year
} else {
// Not a leap year
// Next leap year
Nly = yr + (4 - yr) % 4
}

Answer 4

Davide you don't need make the leap year code as the question is to get the next leap year if year is not leap year.

Answer 5

I deleted the code because I am still confused 🙃 I will post it only if I am 100% sure

Answer 6

CarrieForle you are right, it's just that the ignorance took control of my brain

Answer 7

I had to make it, after all the confusion generated😔

#include <stdio.h>

int main() {

int year;

scanf("%d", &year);

if( (year%4 == 0 && year%100 != 0) || (year%400 == 0) ) {
printf("%d is a leap year\n", year);
}
else {
printf("%d is not a leap year\nThe next leap year is %d\n", year, year+4-year%4);
}

return 0;
}

Answer 8

First, you only need that when the year input is not a leap year, so you need another if statement to check the condition.

Second, you can get the next leap year by adding 4 - year % 4 to the year. But there is an exception that a leap year is not divisible by 100, except if also divisible by 400, you need to increase the year by 4 if it is divisible by 100 and not divisible by 400.

Answer 9

https://www.programiz.com/JUMP_LINK__&&__python__&&__JUMP_LINK-programming/examples/leap-year

Answer 10

Hello.
I had to make it, after all the confusion generated😔

#include <stdio.h>

int main() {

int year;

scanf("%d", &year);

if( (year%4 == 0 && year%100 != 0) || (year%400 == 0) ) {
printf("%d is a leap year\n", year);
}
else {
printf("%d is not a leap year\nThe next leap year is %d\n", year, year+4-year%4);
}

return 0;
}
Here is your answer.
If there is a spelling problem ingnore please
Other I have put right format.....
Thankyou