Ticket Office project

Question

Why am I getting “no output” for this?
int main() {

int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
int ticket = 10;
int small;

int a = ages [0];
int b = ages [1];
etc to [4]

if (a < b && a < c && a < d && a < e)
small = a;
else if (b < c...)
etc
else e = small;

float disc = small * 0.01;
float total = (ticket * 5) * (1.0 - disc);

return total;
}

It works in Code Blocks
Also I had to use “if-else-if” because I couldn’t find how to compare multiple values in a switch.

Answer 1

So I just set the small variable to 100, and used the following;

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
if (ages[i] < small) {
small = ages[i];
}

This simplified the comparison issue. But it took the answer to an entirely different post to fix the “no output” issue I had. After fixing the rest of the code, I had to do “cout” for the answer again.

https://code.sololearn.com/c1QwSR320jnW/?ref=app

Answer 2

Crispy Crunch , why don't you just try to find the younger passenger with loop, without all of the countless conditions you check. For example set the discount variable a big value and in every step of the loop set it to current age if current age is smaller than the discount. As an idea something like this :
int disc = 1000;
for(int i = 0; i < 5; i++){
if(ages[i] < disc){
disc = ages[i];
}
}
All after that is easy calculation.

Answer 3

https://code.sololearn.com/c55aw3oXod29/?ref=app