an output showing the value of a pointer contained a digit x. Why is it so?

Question

Pointer store memory address in hexadecimal An exercise in this app output showing the value of a pointer contained a digit x. Please explain...

Answer 1

I assume that the pointer was dereferenced.

for example:

int* x;
int y = 89;

x = &y;

printf("%p", x);

This would give you the address of y, but if you were to do:

int* x;
int y = 89;

x = &y;

printf("%d", *x);

You should get 89.