someone explain this code? why the output is 9 if you need c++ version of it let me know

Question

import java.io.*;

class GFG {
static int fun(int i)
{
if (i % 2 == 1) return (i++);
else return fun(fun(i - 1));
}

public static void main (String[] args) {
System.out.println(" " + fun(10) + " ");
}
}

// This code is contributed by Shubhamsingh10

Answer 1

Look: initially, when we call the function, we pass it 10, and the condition "10% 2 == 1" is false. So the "else" block is triggered and we call this function, but we already pass 10 - 1 to it, that is, 9 and for 9 the condition "9% 2 == 1" is true, and the function returns "9 ++", that is, it returns 9, which is printed to the console, and then increments this 9

Answer 2

in c++, c #, c, and in all similar languages ​​there will be the same situation

Answer 3

Khaled ^^ خالد القريشي‎

Because 9 % 2 == 1 so i++ will give 9

Answer 4

I said in my question that I can provide the code in C++ as well, instead of posting two question. And it does not really matter what is the language it just needs explanation. Thank you

Answer 5

@Иван Чикyнов very good explanation, Thank you