Regular Expressions , strings

Question

it should return true if the given object is a vowel ( a, e, i, o, u), and otherwise false? My code is not working for all of the strings, I don't understand why?

My code errors: For example : Input "Lol", Output: False. But it should be True, because it has vowel.

My code: oa, when double vowels, also didn't worked

import re
def is_vowel(s):
pattern = r'([AEIOUaeiou])'
match = re.findall(pattern, s)
if match:
return (True)
else:
return (False)

Answer 1

Meka , both strings "oa" and "Lol" give the expected output. So it works.

Answer 2

Meka , remove the brackets "()". You can try this ->
import re
def is_vowel(s):
pattern = r'[AEIOUaeiou]'
match = re.findall(pattern, s)
if match:
return (True)
else:
return (False)
print(is_vowel("oa"))

Answer 3

showing the same results

Answer 4

nope, not really working