Python Regular Expression Practice Quiz "Authentication!"

Question

Hey there, I have some Problems at the Python Practice Quiz "Authentication!"

the input is a Password which shall has
-at least one uppercase character and at least one number

I got some help from google to solve it
and surprisingly I really passed this Quiz but the Code is not right and I have no Idea how to change it, that it works in the right way.

The Problem is: the most Password inputs are recognized correctly (see Examples below) but for example the Password "aA1" which also contains a uppercase character and one number, it shows "wrong format".

Thanks for your Help

my Code:

import re
password = input()

pattern = r"\d.*[A-Z]|[A-Z].*\d"

if re.match(pattern, password):
print("Password created")
else:
print("Wrong format")

Example Inputs -> Outputs:
Aa1 ->Password created
A1a ->Password created
1Aa ->Password created
1aA ->Password created
aA1 ->Wrong format -->should be "Password created"
a1A ->Wrong format -->should be "Password created"

Answer 1

This will help you:

https://code.sololearn.com/car0nA5fk805/?ref=app

Answer 2

Thanks for your replies

I thought this is going to be a a easier Quiz because it is more at the beginning of the Regular Expression Chapter.

The solutuion from Lisa maybe not that Elegant but at least it worked as it should. This helped me a lot.
thanks

this is now my code which is working in the right way:

import re
passwords = ["Aa1", "A1a", "1Aa", "1aA", "a1A", "aA1", "aa1", "aab"]

for p in passwords:
number = re.search("[0-9]",p)
LETTER = re.search("[A-Z]",p)

if bool(number) is True and bool(LETTER) is True:
print("Password created")
else:
print("Wrong format")

Still curious how the single regex would look like ;)

Answer 3

Calvin Sheen Thomas Yeah that was the regex the OP used and was having issues. I ended up using two expressing

numPat = r”[0-9]”
upperPat = r”[A-Z]”

if re. search(numPat, password) and re.search(upperPat, password)

I haven’t sorted a way to get it all in one expression

Answer 4

It tried around and now my regular expression is:

pattern = r"[A-Z0-9]"

and it works exactly as my previous!? ( aA1 and a1A ->Wrong format)

So now I have a shorter Expression but still the same Problem :D

Answer 5

Seems to be a pro quiz 🤔

Is it necessary to use a single regex?
If not we could work around by using one pattern to check for number and one for capital letters (though not very elegant)

passwords = ["aA1", "1Aa", "A11",
"a1a", "Aaq"]
for p in passwords:
number = re.search('[0-9]', p)
LETTER = re.search('[A-Z]', p)
print(p, bool(number), bool(LETTER))

Answer 6

I adapted the example from
https://www.tutorialspoint.com/How-to-check-if-a-string-has-at-least-one-letter-and-one-number-in-JUMP_LINK__&&__Python__&&__JUMP_LINK
to
combi = '^(?=.*[0-9])(?=.*[A-Z])'
and then tried re.match()

Answer 7

Hey Jochen,

Not sure if you sorted this out yet. Have you tried using re.search() instead of re.match()? re.match() starts at the beginning of the string and will return false if their isn't an immediate match. re.search() looks at entire string for a match. I think
pattern = r"[A-Z0-9]" checks for the characters in that order. HAven't figured this out with single regex yet

Answer 8

Cody Knight Your regex expression doesn't give the required results; it just searches for a string which has an upper-case letter OR an integer.

Answer 9

Yup, doing this with two regex is easy. Here's the single regex version: r"([A-Z]+\w*\d)|(\d+\w*[A-Z])"
This works but using two regex is the preferable method for me.

Answer 10

import re
password = input()

pattern = r"[A-Z]+[a-z]*[0-9]+"

if re.search(pattern, password):
print("Password created")
else:
print("Wrong format")

Answer 11

import re
password = input()

#your code goes here
at_least_one_uppercase = "[A-Z]+"
at_least_one_number = "[0-9]+"

if re.search(at_least_one_uppercase, password) and re.search(at_least_one_number, password):
print("Password created")
else:
print("Wrong format")

Answer 12

Maybe?
pattern = r"\d.*[A-Z]|[a-z].\*d"

Answer 13

with this Code Aa1 and A1a also shown as Wrong Format

Answer 14

Here you go:
from re import search as a
b,c=r"([A-Z]+\w*\d)|(\d+\w*[A-Z])",input()
d="Verified" if a(b,c) else "Not Verified"
print(d)
#Might as well copy and paste it in the
#playground.

Answer 15

The simplest expression is as following:

import re
password = input()

#your code goes here
pattern = r".*[A-Z].*[0-9]"

if re.match(pattern, password):
print("Password created")
else:
print("Wrong format")

.* means every character except a line break, a word start is also considered in this. Would you change the pattern to pattern = r"([A-Z])(.*[0-9])" then the password must start with an uppercase character.

------

or even shorter with re.search since this function doesn't care about the start of the string:

import re
password = input()

#your code goes here
pattern = r"[A-Z].*[0-9]"

if re.search(pattern, password):
print("Password created")
else:
print("Wrong format")

Answer 16

Maikel Your code doesn't work for inputs like "8A" and "234LPP". This pattern seems to work with re.search():

r"[A-Z].*\d|\d.*[A-Z]"

Answer 17

You can use this code:

import re
password = r("Enter Your Pass: ")
if re.fullmatch(r'[A-Za-z0-9@#$%^&+=]{8,}', password):
print("Password created")
else:
print("Wrong format")

Answer 18

import re
password = input()

#your code goes here

pattern = r"[A-Z0-9]+"

if re.match(pattern, password):
print("Password created")

else:
print("Wrong format")

Answer 19

If you want to do it as single line, best way is to use lookahead assertion.

r"(? =. *[0-9]). *(? =. *[A-Z])"

It should be working.

Answer 20

Ah and you don't need the. . * between the paretheses.. Because you have them in the lookaheads.

To shorten it:
r"(?=.*[0-9])(?=.*[A-Z])"