Output of C++ code

Question

Why does this code output 4, and not 5?

int x, *y;
x=5;
y=&x;
*y++;
x--;
cout << x;

Answer 1

*y++; <-- your incrementing the pointer...your NOT incrementing the value it's pointing to.
try:
(*y)++.

Answer 2

Because x-- will decremented it's value by 1 so it is 4.

Answer 3

but why doesn’t incrementing y increment x? y stores x’s adress, so why doesn’t x increment as well?

Answer 4

ah ok, thanks rodwynnejones