C++ Pointers

Question

is there a difference between *p1=*p2 and p1=p2?
example in the following code:

#include <iostream>
using namespace std;

int main()
{
int firstvalue = 5, secondvalue = 15;
int * p1, *p2;

p1 = &firstvalue; // p1 = address of firstvalue
p2 = &secondvalue; // p2 = address of secondvalue
*p1 = 10; // value pointed to by p1 = 10
p1 = p2; // p1 = p2 (value of pointer is copied)
*p1 = 20; // value pointed to by p1 = 20

cout << "firstvalue is " << firstvalue << '\n'; // Outputs 10
cout << "secondvalue is " << secondvalue << '\n'; // Outputs 20
return 0;
}

Answer 1

Yes.
p1=p2 copies the adress that is stored in p2 to p1.

*p1 gives you the VALUE of the variable wich is stored in p1.

Example:
Int v1=1;
Int *p1 =&v1;

cout << *p1; gives you "1"
cout << p1; gives you the adress of v1. (Smth like "0x2517af")

Answer 2

but the result will be the same. right ?
the action is different but it causes the same result.
if you do
p1=p2
or
*p1 =*p2.
in both cases after - cout- value is copied.
yes ?