Why is "i-r" ?

Question

Here is the code:

m = 0
for i in range(100):
r = i%22
m = max(m, i-r)
print(m)

I feel like it means to count the max x %22==0 and the answer is 88 indeed. But I still can't figure out why here is "i-r"
yes, i is 99, r is 11, but why?

Answer 1

You can insert print() functions to show what's going on

m = 0
for i in range(100):
print("i =", i)
r = i%22
print("r =", r)
m = max(m, i-r)
print("i - r =", i - r)
print("m =", m)
print(m)

Answer 2

print(max(i for i in range(100) if i % 22 == 0)) is simpler

Answer 3

99 - 11 = 88
its a minus

Answer 4

Yes, it prints the largest multiple of 22 that is less than 100.

i - r = i - i % 22
i - i % 22 gives you the largest multiple of 22 that is less than i, just like math.floor(i / 22) * 22.

The intuition behind it is that the remainder i % 22 is "how many steps do you have to go down from i to reach a multiple of 22". Let's say i = 67. We know that 66 is the largest multiple of 22 that is less than 67. In order to go from 67 to 66 you subtract 1. 67 % 22 happens to be 1.

Answer 5

print(max(I for i in range(100)if i % 22==))
I think it is right