What is happening in this code?

Question

Output of below code is h , plz explain how ? What happens when we use operator * or & more than once in same line ?
int main()
{
char *ptr = "helloword";
printf("%c\\n", *&*&*ptr);
return 0;
}

Answer 1

Here your decleared *ptr pointer which type is char type and u storing helloworld in printf statement u use %c after that \\n Slash work as separatator so if u will write two slash it single Slash will be print then *ptr will point first char &ptr will print address then *&ptr again pointing first char then & address then * for value.
So that *&*&*ptr will point value which is first char h
So output will be
h \n

Answer 2

Thank you Syrah Algena . Now I get it . The extra slash is by mistake , by the way \n is unusable there .
So, in simple (*,&) these operators cancel out effect of each other when used one after another?

Answer 3

Hrutik Bhalerao yeah

Answer 4

Pointr 0 +1 +2 +3 +4 +5 +6 +7 +8
Vaue. h e l l o w o r d

Pointr its a address of cell in memory
Value its a char in cell.