basic python help (again)

Question

number = input("the number ")

try:
if number is not int:
print(number + " Is not a number!")
else:
print("Valid!")
except:
print("a")
raise

the code considers numbers not a number too, so its going to execute the if statement no matter what i put in

Answer 1

Ok6c , as long as you are not forced to use a try... except... block, you can just use string.isdigit() method like this:

number = input("the number ")

if not number.isdigit():
print(number. "Is not a number!")
else:
print("Valid!")

but this is only working while using integer numbers. if you also want to check floats, you can perform a conversion in a try... except block.

Answer 2

Use "if not number.isdigit():"

Answer 3

open world games channel type for number will be string unless you convert it to int explicitly like type(int(number))

Answer 4

if number is not int:

return True if number is not the int class.

as number hold the input() return value, number is always a string.
however, if number is str return False also, as number is a str instance, not the str class itself...

checking for number inputed could be done by multiple ways, among wich try/except blocks:

try:
number = int(input())
# if number no error raised
print('an integer')
except:
print("not an integer")

... or by one of the already given answer ;)

Answer 5

Use type if type(number)!=int:
print(f"{number} is not a number")
else:
print("valid")
except some error as err:
print(err)