help with loops in python

Question

count = 0
while True:
userName = input("Username: ")
password = input("Password: ")
count += 1
if count == 3:
print('Too many login attempts. Goodbye.')
break
else:
if userName == 'student' and password == 'abc123':
print ("Login attempt sucessful!\n")
print('\n''GAMES \n------------')
print('1. Print the Pattern')
print('2. Guess the Number')
print('3. Logout')
print ("\n\n")
x=input ('>>Enter option: ');
print('\n\n\n')#let them in

while x in '1':
print('Print the Pattern')
z = input('Enter a whole number: ')
n = int(z)
s = input('Enter a symbol: ')
for i in range(n):
for j in range(i+1):
print(s,end='')
print()

import random
randAns = random.randint(0, 100)
numberOfGuesses = 0
while x in '2':
print('Guess the Number')
# reading number from user
ans = int(input('Between 0 and 100 : '))
print('\n')
# incrementing numberOfGuesses
numberOfGuesses += 1
# if user input matches the generated number
# prints correct number and stops the loop
# if user input is less it prints guess is less
# else prints guess is greater than random number
if ans == randAns:
print('YOU GOT IT!')
break
elif ans < randAns:
print('TOO LOW! \nGUESS AGAIN!')
print('\n\n\n')
elif ans > randAns:
print('TOO HIGH! \nGUESS AGAIN!')
print('\n\n\n')
if x in '3':
print('Goodbye. See you soon.')
print('\n\n\n')
else:
print('Invalid Option')

Answer 1

What is the error ? What does program do ? For what input are you getting an error ? If you can add those in description as well , it might be easier for someone to help.

Answer 2

Gutz_X_73vEn copy paste the code in python file , and share the code link here as i think there is limitation on characters for description.

Answer 3

Gutz_X_73vEn it is working fine. The only problem i see is the 2 option where while loops forever.

Answer 4

Gutz_X_73vEn sorry, i meant 1st one , just use ( if x in '1' in place of while ) if you want user to print pattern once only.

Answer 5

oh perfect that makes since this was my first loop excercise thank you Abhay!

Answer 6

Gutz_X_73vEn also this code works 2 two times only because you are increasing count before "if count==3" , instead place it after "else".

if count == 3:
print('Too many login attempts. Goodbye.')
break
else:
count+=1
if userName == 'student' and

there are few other things as well that can be corrected , so i will edit it and let you know later on.

Answer 7

https://imgur.com/gallery/ijnUKmz

https://imgur.com/gallery/LLztWk0

https://imgur.com/gallery/70Dk22s

Answer 8

Abhay i tried sending in pm but wouldn’t send so i put link to videos here

Answer 9

oh sorry lol it cut out my explanation

Answer 10

so its supposed to be a game library with 2 simple games

1 guess the number
2print the pattern
and 3 is logout which should take back to the login menu

i need it to give three attempts to login and display how many are left and if you go over 3 attempts i need it to say too many login attempts

then i need the games to loop back to the main menu after playing once

Answer 11

i
https://code.sololearn.com/ca24a21a20a2/?ref=app

Answer 12

sorry it looks kinda crappy on mobile lol

Answer 13

i just need it to loop back to the select menu after each time you play a game

Answer 14

oh thank you so much that really helps im trying to juggle too many classes at once but im going back over the basics again !!

Answer 15

Instead of break use continue hope it would work