Delete the greater number from a big number using just while loop

Question

Input
5912
Output
512

Answer 1

What if it takes more than 1 while-loop? does it have to be done with 1 while-loop?

What if there are multiple greatest digit? e.g. 2021 (digit 2 appear twice)

And what if all the digits are the same? e.g. 999

Answer 2

I tried, but I couldn't get it to work as expected if I must strictly use only 1 while-loop ...

Answer 3

Ipang agree with you but any idea?

Answer 4

Ipang pang try with multiple while loop

Answer 5

My confirmation remains unanswered ... what if there are multiple greatest digit? and what if all digits are the same?

Answer 6

Here it uses 2 while loop. First one searches for largest digit, and second one builds the resulting number.

https://code.sololearn.com/ckC9l6ULuP9N/?ref=app

Answer 7

#include <iostream>
using namespace std;
int main()
{ int N,uc,c,y=0,p=1;
cin>>N;
;
while(N!=0){
uc=N%10;
if(max(uc,9))
c=uc*0;
N=N/10;
if(N%10!=0){
y=(N%10)*p+y;
p=p*10;
}

}

cout << y;

return 0;
}

Answer 8

this I try

Answer 9

Mirielle[ INACTIVE ] the program should see all numbers from that number and delete the biggest one

Answer 10

You have numbers till 9 so if you have a number like 9987 output will be 87

Answer 11

But is not specify the particulars cases