How these loop execute ?

Question

for(x=0;x=10;x++);

Answer 1

Shubham Maske

If you print value of x then this loop will work till infinite because after incrementing value of x you again assign with 10 (x=10) so output will be 10101010101010101010................. Execution Timeout.

Try this code in Code Playground.

int x = 0;

for (x = 0; x = 10; x++) {
cout << x;
}

Answer 2

It's an infinite loop if you wrap the condition in parentheses.

Answer 3

Shubham Maske

#include <iostream>

int main() {

for(int x=0;x < 10;x++) {
std::cout << x << std::endl; }
return 0;
}

Answer 4

The condition for the entry of the loop is wrong

Answer 5

for(x=0;x=10;x++);
Output; null
This condition is stop , don't executed the loop.

for(x=0;x=10;x++)
{
Printf(x);
}
Output 0123456789