Trouble with Halloween Candy

Question

I can't solve this exercise. If i find the solito for case 1-2 It isn't right for the other cases and the other Way around.

Answer 1

Output should be rounded up to the nearest integer. So you need to use ceil() for both conditions :)

if (final >= .5){
printf("%.f", ceil(output));
}
else{
printf("%.f", ceil(output));
}

Answer 2

Yup!
It rounds up to the nearest integer.
Check it out for reference

https://code.sololearn.com/cWf030i39pru/?ref=app

Answer 3

Thank you 🙏

Answer 4

Cristopher Ricciotti
Try this maybe help you:

#include <stdio.h>
#include <math.h>
int main() {
int houses;
scanf("%i", &houses);
if(houses>=3){

printf("%i",(int)ceil(200.0/houses)); }
return 0;
}

Happy coding 👍😃

Answer 5

#include <stdio.h>
#include <math.h>
int main() {
float houses;
scanf("%f", &houses);

float dollar = 2;
float output = (dollar / houses)*100;

int res;
res = (int)output;

float final;
final = output - res;

if (final >= .5){
printf("%.f", ceil(output));
}
else{
printf("%.f", floor(output));
}

return 0;
}

Actually this Is the last version

Answer 6

But ceil() should round up to the biggest, or not? 🤔