How the value of count is 11

Question

https://code.sololearn.com/ck6vxvSEb4kz/?ref=app

Answer 1

the syntax is wrong for the second for loop and i<=10 means it will go till ten then when it goes inside the loop with 10 it count++ increments So 10 becomes 11

Answer 2

Your both loops are altering same loop variable (*i*), so by the end of the first loop, the value of *i* is 11 already, and then program also goes out of outer loop also.