PYTHON. count the word in text by using def.

Question

THIS IS MY CODE. PLEASE HELP ME FIX IT. ( there are 2 input: text and word)

def word_count(text, word):
if word in text:
return text.count(word))
text = input()
word = input()
x=word_count(text, word)
print(x)

Answer 1

here is an similar solution:

def word_count(text, word):
return text.count(word)

text = input().split()
word = input()
print(word_count(text, word))

Answer 2

you doesn't need the 'if' statement in your code (if not word in text, you'll return None instead of 0)...

however, your logic is not good: counting 'java' in 'javascript' would report 1, while 0 is expected ^^

you must split the text into words, and count occurence of target word inside the array ;)

Answer 3

You have excess closing parentheses in `word_count` function return statement.

return text.count(word) # <- remove excess ')'

Answer 4

If you don't use def, just
print(input().split().count(input()))

Answer 5

Try this :

def word_count(text, word):
if word in text:
res = text[0:].split(' ')
return res.count(word)
text = input()
word = input()
print(word_count(text, word))