Take a number N as input and output the sum of all numbers from 1 to N (including N). Python code

Question

No one likes homework, but your math teacher has given you an assignment to find the sum of the first N numbers.

Let’s save some time by creating a program to do the calculation for you!

Take a number N as input and output the sum of all numbers from 1 to N (including N).

Answer 1

n=int(input())
print((n+1)*n//2)
This is perfectly right code

Answer 2

N = int(input())
x=0
for i in range (0, N+1):
x+=i
print(x)

this worked for me perfectly

Answer 3

N = int(input())
SUM = int()
O = int()
for O in range(0,N+1,1):
SUM = SUM + O
print(SUM)

Answer 4

Pratik Chordiya

1) don't mark your own answer as best

2) this code is perfectly fine by itself, but the task expect you to practice loop ^^

Answer 5

There is a formula to calculate sum of first n natural numbers which is,
S = n(n+1)/2

You can solve this problem by applying the formula,
n=int(input("Enter n: "))
print("Sum is:",n*(n+1)//2)

But if you don't know the formula, no need to worry. You can simply use a looping construct to solve this problem.

n,s=int(input("Enter limit: "), 0
for i in range(1,n+1):
s+=i
print("Sum:",s)

Answer 6

n = input("Enter N \n")
n=int(n);

total=0
for i in range(n+1):
total+=i
print("sum = "+str(total))

Answer 7

num = 358
if num < 0:
print("Enter a positive number")
else:
sum = 0
while(num > 0):
sum += num
num -= 1
print(sum)

Answer 8

N = int(input())
SUM = int()
O = int()
for O in range(0,N+1,1):
SUM = SUM + O
print(SUM)

Answer 9

N = int(input())
sum = 0
for x in range(N + 1):
sum = sum + x
print(sum)

##hope it helps

Answer 10

print((n+1)*n/2)

I have the feeling it is YOUR time that is to be saved.

Answer 11

Thank u visph

Answer 12

(n+1)*n//2

Answer 13

#include <iostream>
using namespace std;

int main() {

int n;

cin >> n;

int sum=0;

for(int i=1;i<=n;i++)
sum+=i;

cout << sum;

return 0;

}

Answer 14

Your's both of code it's perfectly right thank u both of you. visph Frogged

Answer 15

(n+1)*n//2

Answer 16

n=int(input())
print((n+1)*n//2)

done...!

Answer 17

N = int(input())
#your code goes here
R = range(0 , N)

print (sum(R)+N)

Clean

Answer 18

No one likes homework, but your math teacher has given you an assignment to find the sum of the first N numbers.

Let’s save some time by creating a program to do the calculation for you!

Take a number N as input and output the sum of all numbers from 1 to N (including N).

Sample Input
100

Sample Output
5050

Explanation: The sum of all numbers from 1 to 100 is equal to 5050.

N = int(input())
SUM = int()
O = int()
for O in range(0,N+1,1):
SUM = SUM + O
print(SUM)

for all doubt solving contact on this by telegram
https://youtu.be/tOWQqOWieE4

Answer 19

N = int(input())
num = int()
sum=0
for num in range(0,N+1):
sum += num
print(sum)

This code works. Try it

Answer 20

N = int(input())
#your code goes here
print(sum(range(1,N+1)))

Very easy to solve this problem