BMI Calculator (Python3)

Question

Hey, I've been trying to figure out the BMI Calculator problem. Can someone please help me?
Here is what I've written so far:

weight = int(input())
if weight < 18.5:
print("Underweight")
else:
if weight >= 18.5 and < 25:
print("Normal")
else:
if weight >= 25 and < 30:
print("Overweight")
else:
if weight > 30:
print("Obesity")
--
I get the error:
---
File "/usercode/file0.py", line 5
if weight >= 18.5 and < 25:
^
SyntaxError: invalid syntax

Answer 1

hi! you don't compare anything to <25

Answer 2

On either side of the AND, you need to write a full evaluation. weight > 18.5 and weight < 30. You need this in all your tests. However, the better method is to use if / elif:

if weight < 18.5:
print(“Underweight”)
elif weight < 25:
print(“Normal”)
elif weight < 30:
print(“Overweight”)
else:
print(“Obesity”)

This method simplifies the tests and because of using elif, you don’t have to test for conditions already found above.

Answer 3

It should like
if weight>= 18.5 and weight < 25 :

Or simply (in python)
if 25 > weight >=18.5:

Answer 4

Ohh, thank you! I'm one step closer to completing it now. I'll do the rest by myself.

Answer 5

w = float(input())
h = float(input())
x = ("w/h**2")
if x < 18.5:
print("Underweight")
elif x < 25:
print("Normal")
elif x < 30:
print("Overweight")
else:
print("Obesity")

And
Traceback (most recent call last):
File "/usercode/file0.py", line 4, in <module>
if x < 18.5:
TypeError: '<' not supported between instances of 'str' and 'float'

Answer 6

Weight=int(input())
Height=float(input())
Bmi= Weight/(Height*Height)
if Bmi < 18.5:
print("Underweight")
elif Bmi < 25:
print("Normal")

elif Bmi < 30:
print ("Overweight")
else:
print ("Obesity")

It took a while but I was able to get the results with this method. Try and see if it works.