Python for Data Science - House Prices

Question

You are given an array that represents house prices.
Calculate and output the percentage of houses that are within one standard deviation from the mean.

To calculate the percentage, divide the number of houses that satisfy the condition by the total number of houses, and multiply the result by 100.

I stuck at this question, can anyone help out?

This is my code : https://code.sololearn.com/cA255a72a21A

Answer 1

you rather need to output percentage of data than count:

print(100*count/data.size)

Answer 2

My code

import numpy as np

data = np.array([150000, 125000, 320000, 540000, 200000, 120000, 160000, 230000, 280000, 290000, 300000, 500000, 420000, 100000, 150000, 280000])

m = np.mean(data)
s = np.std(data)
low = m-s
high = m+s

print(
len(data[(low < data) & (data < high)])
/ len(data) *100
)

Answer 3

import numpy as np

data = np.array([150000, 125000, 320000, 540000, 200000, 120000, 160000, 230000, 280000, 290000, 300000, 500000, 420000, 100000, 150000, 280000])

mean = np.mean(data)
std = np.std(data)
low = mean-std
high = mean+std
count = 0

for i in data:
if low < i < high:
count += 1

result = (count / len(data))*100

print(result)

Answer 4

Hi! here's my answer

m = np.mean(data)
d = np.std(data)
y1 = m-d
y2 = m+d
s = len(data [(data > y1) & (data < y2)])
r = (s/len(data))*100
print(r)

I hope it helped!

Answer 5

import numpy as np

data = np.array([150000, 125000, 320000, 540000, 200000, 120000, 160000, 230000, 280000, 290000, 300000, 500000, 420000, 100000, 150000, 280000])

one line answer✌️

print(len([i for i in data if i > (np.mean(data) - np.std(data)) and i < (np.mean(data) + np.std(data))]) / len(data) * 100)

Answer 6

A short and simple answer for the problem:

mean = np.mean(data)
std = np.std(data)

x=(data[(data <= mean+std) & (data >= mean-std)])

print(x.size/data.size*100)

Answer 7

Lai Kai Yong: Please help me with the first Python for Data Science Basketball Players exercise.

Answer 8

import numpy as np

data = np.array([150000, 125000, 320000, 540000, 200000, 120000, 160000, 230000, 280000, 290000, 300000, 500000, 420000, 100000, 150000, 280000])

mean = np.mean(data)
std = np.std(data)

result = data[np.logical_and(data <= mean + std, data >= mean - std)]

print(result.size/data.size*100)

Answer 9

print(len([i for i in data if (np.mean(data)-np.std(data))< i < (np.mean(data)+np.std(data))])/len(data)*100)

Answer 10

import numpy as np

data = np.array([150000, 125000, 320000, 540000, 200000, 120000, 160000, 230000, 280000, 290000, 300000, 500000, 420000, 100000, 150000, 280000])

strd=np.std(data)
means=np.mean(data)

alt=means-strd
ust=means+strd
a=(data>alt)&(data<ust)

print((len(data[a])/len(data))*100)

Answer 11

import numpy as np

data = np.array([150000, 125000, 320000, 540000, 200000, 120000, 160000, 230000, 280000, 290000, 300000, 500000, 420000, 100000, 150000, 280000])

low = np.mean(data)-np.std(data)
high = np.mean(data)+np.std(data)

print (len(data[(data>low)&(data<high)])/len(data)*100)

Answer 12

you must compute the mean of your data, then compute the standard deviation and finally count how many data are in the range mean-deviation, mean+deviation...

Answer 13

@visph, I'm still confuse. I had modified my codes but it shows an output but still wrong.

Answer 14

Lai Kai Yong check again my previous edited post: np.std should get data as argument ^^

Answer 15

@visph, it does not work...

Answer 16

Bruno it havent helped

Answer 17

import numpy as np

data = np.array([150000, 125000, 320000, 540000, 200000, 120000, 160000, 230000, 280000, 290000, 300000, 500000, 420000, 100000, 150000, 280000])

mean = np.mean(data)
std = np.std(data)
low = mean-std
high = mean+std
count = 0

for i in data:
if low < i < high:
count += 1

result = (count / len(data))*100

print(result)

Answer 18

data = np.array([150000, 125000, 320000, 540000, 200000,
120000, 160000, 230000, 280000, 290000, 300000, 500000,
420000, 100000, 150000, 280000])

mean = np.mean(data)
std = np.std(data)
a=mean+std
b=mean-std

c=(data[(data <= a) & (data >= b)])

print(c.size/data.size*100)

Answer 19

COVID Data Analysis

You are working with the COVID dataset for California, which includes the number of cases and deaths for each day of 2020.
Find the day when the deaths/cases ratio was largest.

To do this, you need to first calculate the deaths/cases ratio and add it as a column to the DataFrame with the name 'ratio', then find the row that corresponds to the largest value.