Can anyone explain this

Question

Class A{
private int a ;
Public void age (int a) {
Sout("your age is :" + (2021-a)) ;
}
Public class main{
P. S. V. M(S[] args) {
A d=new A() ;
d.age(12);
Generally we can't access private members but here instead of using get and set methods I have passed through the argument now the code is working what's the use of private Why it's not popping an error?

Answer 1

In the class A, the method age() has a parameter named a of type int. Since you're doing '2021 - a' inside the method, the parameter is being subtracted and not the instance variable 'a' present in the class because the variable 'a' is present in the scope of the method as a parameter. In fact, the instance variable is not even used once throughout the code.

Even if you were to change the parameter variable of the method, the code would still work (assuming 'a' was initialized) because you're not directly accessing the private instance variable a but using a public method that has access to the private member.

Edit : Here's a code for better understanding.

https://code.sololearn.com/cqylt8Iz0SKz/?ref=app

Answer 2

D_Stark yeah sout is the short form of printing line and yeah I've just given the overview

Answer 3

// more readable
class A {
private int a;

void age (int a) {
System.out.println("your year of birth is: " +(2021-a) );
}
}
public class Main {
public static void main(String[] args) {
A d = new A();
d.age(12);
}
}

Answer 4

This doesn't look like a java code as your using cout. Also when refrencing a instance variable inside a method and your parameter has the same name you should use this.a = a