Is there a way to do this more efficiently? Spylife

Question

https://code.sololearn.com/c6471EpWb3Tv/?ref=app

Answer 1

Tarun Kumar Aggarwal
Instead of making a list of alphabets, you can simply use str.isalpha() to check if a character is an alphabet.
https://code.sololearn.com/cys855C11tXa/?ref=app

There is also a one-line way to do the using the filter() function, but I'm guessing you're not familiar with it currently.

Answer 2

XXX
You're right. But for this special code coach use case, you have also to consider the "blank"
if char.isalpha() or char==' ':

Answer 3

What are you trying to do here? Are you simply trying to reverse a string. Then the for-loop is unnecessary. Only `codedtext[::-1]` is enough.

Answer 4

This is an exercise in code coach. The input string will have special characters and numbers which the program needs to remove and then reverse the string

Answer 5

Thanks XXX

Answer 6

Here is a streaming approach that does not retain the whole result. It uses fewer lines of code and fewer variables:

buf = input()

for ch in buf[::-1]:
if (ch.isalpha() or ch==' '):
print(ch, end="")