Can anyone help me to understand this question?

Question

Im a little new here and I've been trying to use JavaScript loops to solve this problem but I just can't seem to get my head around it.

Question :
The snail climbs up 7 feet each day and slips back 2 feet each night.
How many days will it take the snail to get out of a well with the given depth?

Sample Input:
31

Sample Output:
6

Explanation: Let's break down the distance the snail covers each day:
Day 1: 7-2=5
Day 2: 5+7-2=10
Day 3: 10+7-2=15
Day 4: 15+7-2=20
Day 5: 20+7-2=25
Day 6: 25+7=32
So, on Day 6 the snail will reach 32 feet and get out of the well at day, without slipping back that night.

Answer 1

and the logic is independent of the programming language. if you have the wrong algorithm, you will also solve it incorrectly on python for example. I'm trying three languages: js, python, and ruby. and imagine, the logic is the same! only the syntax of writing the program differs

Answer 2

There is one 🐌 and it is daily climbs the wall 7 feet up but at night it slips out 2 feet. means it slips from 7 feet so 7-2 = 5.

Now you have to figure out how many days it takes to get out from particular given depth.

In question input is 31 so 31 is total feet you have. now if 🐌 is climb 7 feet at day and slip 2 feet at night so in 1 entire day it climb only 5 feet.
so 31-5 = 26 feet is still remains.

now next day it again climb 7 feet and slips 2 feet so. 1st 5feet + 7feet - 2feet slips =10.

Two entire day is completed. and snail is climbed 10 feet. still snail have to climb 21 feet

Answer 3

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var day = depth / (5);

console.log(Math.round(day));
}

Answer 4

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var day = depth / (5);

console.log(Math.round(day));
}

Answer 5

Look at my post it's solution and is too easy to understand...

Answer 6

Post is closed

Answer 7

Discussion is closed...

Answer 8

Question is closed...

Answer 9

Ask something ELSE!!!

Answer 10

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var day = depth / (7-2);

console.log(Math.round(day));
}

Answer 11

Tapabrata Banerjee you solved this task?

Answer 12

why do you get attached to five instead of seven? that's not how it works there

Answer 13

With your skills, you can work as an error generator in the code for the testers service 🤭

Answer 14

The solution is to round off your result..
the code will be:
// without slips back at night.
var day = depth / (7-2);
//to print out put and round the result.
console.log(Math.round(day));

Answer 15

Hi! Can you show us your code attempt?

Answer 16

I have not completely solved this problem, but I think that you are suggesting the wrong thing. think about when the snail should come out? and when should I check it out or not?

Answer 17

In simple input / 5. if it is less than or equal to (<=0) than return that number otherwise add 1 in that

Answer 18

we had a heated discussion here, but nothing came from the owner of the question... what does he think about it? welcome to join us!

Answer 19

Tapabrata Banerjee you forgot print command number of days

Answer 20

and why do you need the "d" - counter variable when the "i" loop variable does a great job of it