+ 1

Can i use this:in range(-100,100,0.1)

14th Apr 2021, 11:51 AM
Ī˜ĪŸĪ”Ī©Ī”Ī—Ī£ Ī¦Ī•Ī”Ī•ĪĪ¤Ī™ĪĪŸĪ£
Ī˜ĪŸĪ”Ī©Ī”Ī—Ī£ Ī¦Ī•Ī”Ī•ĪĪ¤Ī™ĪĪŸĪ£ - avatar
4 Answers
+ 2
Range stepping requires an integral value. Next time you have a doubt, try it out first šŸ‘
14th Apr 2021, 11:55 AM
Ipang
+ 1
Ipang of course i tried but the majority of languages can do this. So i thought i done something wrong. Thank you!
14th Apr 2021, 11:57 AM
Ī˜ĪŸĪ”Ī©Ī”Ī—Ī£ Ī¦Ī•Ī”Ī•ĪĪ¤Ī™ĪĪŸĪ£
Ī˜ĪŸĪ”Ī©Ī”Ī—Ī£ Ī¦Ī•Ī”Ī•ĪĪ¤Ī™ĪĪŸĪ£ - avatar
+ 1
This comes close, but I'm seeing occasional repetition, maybe you can fine tune it further n =- 100.0 for i in range( -100, 100, 1): print( f'{n:.2f}' ) for j in range( 1, 10 ): n += 0.1 print( f'{n:.2f}' )
14th Apr 2021, 12:14 PM
Ipang
+ 1
# Hi! With ā€™inā€™ you test if the number is in the range: it becomes True or False. But your step size is a problem, and floats is a source to round off ertors. So use range to build (for example) a list that includes all the numbers in the range: # Is 11.7 in the range [10.0, 10.1, ...., 11.9]? n = 11.7 l = [k/10 for k in range(100, 120)] print(l) print(n in l) # Is 11.7 in the range? # If you donā€™t like long lists, you can just swap the [brackests] to (parentheses) to get generator onstead: n2 = 10.3 l2 = (k/10 for k in range(100, 120)) print(l2) print(n2 in l2) # Is 10.3 in the range? # Using 0.1*k instead of k/10 will likely result in round off errors. https://code.sololearn.com/cVMYh4OmHWER/?ref=app
14th Apr 2021, 6:27 PM
Per Bratthammar
Per Bratthammar - avatar